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Proof step 9 from proof odd-mult (previous step)

¬(∃ m0. 2 * m0 = m) ∧ ¬(∃ m0. 2 * m0 = n) ⊦ ¬(∃ m0. 2 * m0 = m * n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information