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Proof step 6 from proof add-assoc (previous step)

⊦ ⌜m0 + m1⌝ + ⌜m⌝ = ⌜m0⌝ + ⌜m1⌝ + ⌜m⌝

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝

Rule argument

spec: nat-inf inst: name: add-fin seq: ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ subst: [n, m] → [m, m0 + m1] flags: rewrite, current

Additional information

Used simplifier rules: add-fin: ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ ;%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: m, m0 + m1