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Theorem add-assoc
⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2
Type: A user defined theorem
Validity: The proof is valid.
Features: localsimp, simp,
Comment:
Used by:
add-all-zero
,
add-cancel-01
,
add-cancel-02
,
add-cancel-03
,
add-cancel-num-01
,
add-cancel-num-02
,
add-cancel-num-03
,
add-cancel-num-04
,
add-inf-01
,
add-inf-02
,
add-less
,
add-less-fin-01
,
add-ls-cancel-01
,
add-ls-cancel-num-01
,
add-ls-cancel-num-02
,
add-ls-cancel-num-03
,
add-ls-cancel-num-04
,
add-not-less
,
addeqinf-cancel
,
eqls-ls-notls
,
eqls-succ
,
eqsucc-ls
,
eqsucc-notls
,
eqsum-notless
,
inf-inseq-reduce
,
leq-notgradd
,
less-less-leftsucc
,
less-notgeqinf
,
less-succ-leq
,
ls-lsadd
,
ls-notlssucc
,
ls-succ
,
ls-succ-01
,
num-add
,
rem-seln-on-add
,
sum-notinf
,
sum-zero
,
sum-zero-fin
,
Used by units in proved state:
stream
,
stut-mon
,
mon-lim-filter-count
,
streamseq-mon-lim
,
inf-app-list
,
infinite-append
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 4
Proof steps: 5
Used lemmas:
add-fin
,
add-inf2
,
add-inf1
,
add-comm
,
add-all-inf
,
Used spec theorems:
Used simplifier rules:
nat-basic2
/
a
nat-basic2
/
c