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Proof step 1 from proof ls-03-num (conclusion)
m ≤ n, m ≠ 0 ⊦ (* n) * n0 < (* m) ↔ n0 = 0
Special step normalize
And obtained the following new goals
Proof step 2
:
m ≤ n, m ≠ 0 ⊦ n * n0 < m ↔ n0 = 0