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Proof step 2 from proof ls-03-num (previous step)

m ≤ n, m ≠ 0 ⊦ n * n0 < m ↔ n0 = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-03: ⊦ m ≤ n ∧ m ≠ 0 → (n * n0 < m ↔ n0 = 0);%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;%zero: ⊦ 0 * n = 0;%zero: ⊦ 0 < m ↔ m ≠ 0; from specification nat-basic1