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Theorem rsucc-01
⊦ (m + 1) * n = m * n + n
Type: A user defined theorem
Validity: The proof is valid.
Features: dist-split, localsimp,
Comment:
Used by:
dist
,
dist-sub-01
,
dist-sub-02
,
eq
,
eq-01
,
le-03
,
leone
,
ls-01
,
ls-08
,
lssucc
,
lssucc-01
,
mod-neq
,
mod-neq-03
,
mod-neq-05
,
modeq
,
mult-c
,
mult-eq-succ
,
nonumsimp-eqsucc
,
nonumsimp-lstwo
,
nonumsimp-mod-neq
,
nonumsimp-mod-neq-05
,
nonumsimp-succ
,
nonumsimp-twols
,
numeral-10
,
numeral-17
,
numeral-19
,
numeral-20
,
numeral-21
,
numeral-23
,
numeral-24
,
numeral-25
,
numeral-26
,
numeral-27
,
numeral-28
,
numeral-30
,
numeral-32
,
numeral-35
,
numeral-36
,
one
,
one-01
,
rsucc
,
sqr-07
,
square-eq
,
square-eq-01
,
square-even
,
square-even-01
,
square-inject
,
square-interval
,
square-le
,
square-le-01
,
square-ls
,
square-ls-01
,
square-ls-02
,
square-ls-04
,
succ
,
succ-merge
,
three
,
threeeq
,
threels
,
two-succ-03
,
twols-01
,
zero-01
,
zero-03
,
zero-05
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 0
Proof steps: 3
Used lemmas:
rsucc-02
,
mult-a
,
mult-base
,
Used spec theorems:
Used simplifier rules:
nat-basic2
/
eq-01
nat-basic2
/
c
nat-basic2
/
a
nat-basic2
/
succ