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Proof step 4 from proof square-even (
previous step
)
(∃ n. m = 2 * n) ∨ (∃ n. m = 2 * n + 1), m * m + m = 2 * n + 1 ⊦
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
m * m + m = 2 * n + 1, m = 2 * n0 ∨ m = 2 * n1 + 1 ⊦
Rule argument
Additional information