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Proof step 5 from proof square-even (previous step)

m * m + m = 2 * n + 1, m = 2 * n0 ∨ m = 2 * n1 + 1 ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 6:
m = 2 * n0, m * m + m = 2 * n + 1 ⊦
Proof step 9:
m = 2 * n1 + 1, m * m + m = 2 * n + 1 ⊦

Rule argument

pos: left 2

Additional information