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Proof step 6 from proof square-even (previous step)

m = 2 * n0, m * m + m = 2 * n + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
4 * n0 * n0 + 2 * n0 = 2 * n + 1 ⊦

Rule argument

Additional information

Used simplifier rules: mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;