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Proof step 4 from proof square-le-02 (previous step)

m * m ≤ n * n, n < m ⊦ m = 0

User applied rule cut formula

And obtained the following new goals

Proof step 5:
n * n < m * m, m * m ≤ n * n, n < m ⊦ m = 0

Rule argument

fma: n * n < m * m

Additional information

Used simplifier rules: ls-06: ⊦ m < m0 ∧ n < n0 → m * n < m0 * n0;%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m; Used formulas: n * n < m * m