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Proof step 5 from proof square-le-02 (
previous step
)
n * n < m * m, m * m ≤ n * n, n < m ⊦ m = 0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 6
:
⊦ m ≤ n ↔ ¬ n < m
Rule argument
spec: nat inst: name: le-def seq: ⊦ m ≤ n ↔ ¬ n < m subst: [n, m] → [n * n, m * m] flags: rewrite
Additional information
Used terms: n * n, m * m