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Proof step 19 from proof enc-invert (
previous step
)
¬ m - n0 ≤ maxenc(m), maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ m < n0, (((maxenc(m) - (m - n0)) + (m - n0)) * ((maxenc(m) - (m - n0)) + (m - n0) + 1)) / 2 + (m - n0) = m
User applied rule weakening
And obtained the following new goals
Proof step 20
:
¬ m - n0 ≤ maxenc(m), maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ m < n0
Rule argument
poslist: right 2
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