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Proof step 20 from proof enc-invert (previous step)

¬ m - n0 ≤ maxenc(m), maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ m < n0

User applied rule insert lemma

And obtained the following new goals

Proof step 21:
⊦ maxenc(m) * (maxenc(m) + 1) ≤ 2 * m ∧ 2 * m < (maxenc(m) + 1) * (maxenc(m) + 2)
Proof step 22:
maxenc(m) * (maxenc(m) + 1) ≤ 2 * m ∧ 2 * m < (maxenc(m) + 1) * (maxenc(m) + 2), ¬ m - n0 ≤ maxenc(m), maxenc(m) * (maxenc(m) + 1) = 2 * n0 ⊦ m < n0

Rule argument

spec: nat-pair inst: name: max-size-01 seq: ⊦ maxenc(m) * (maxenc(m) + 1) ≤ 2 * m ∧ 2 * m < (maxenc(m) + 1) * (maxenc(m) + 2) subst: [m] → [m] flags: current, []

Additional information

Used terms: m