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Proof step 6 from proof ltwo-03 (previous step)

⊦ 2 * 2 ^ log2 n ≤ 2 * n, log2(2 * n) = log2 n + 1, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ m ≤ n ↔ ¬ n < m
Proof step 8:
⊦ ¬ 2 * n < 2 * 2 ^ log2 n, log2(2 * n) = log2 n + 1, n = 0

Rule argument

spec: nat inst: name: le-def seq: ⊦ m ≤ n ↔ ¬ n < m subst: [n, m] → [2 * n, 2 * 2 ^ log2 n] flags: rewrite

Additional information

Used terms: 2 * n, 2 * 2 ^ log2 n