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Proof step 8 from proof ltwo-03 (previous step)

⊦ ¬ 2 * n < 2 * 2 ^ log2 n, log2(2 * n) = log2 n + 1, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
n < 2 ^ log2 n ⊦ n = 0, log2(2 * n) = log2 n + 1

Rule argument

Additional information

Used simplifier rules: two-pot-zero: ⊦ 2 ^ n ≠ 0;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%ls: ⊦ m0 * m < m0 * n ↔ m0 ≠ 0 ∧ m < n; from specification nat-mult