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Proof step 39 from proof divi-same (previous step)

m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, m | n3

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 40:
⊦ m | n ↔ (∃ n0. m * n0 = n)
Proof step 41:
m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, ∃ n0. m * n0 = n3

Rule argument

spec: nat-prime inst: name: Divides seq: ⊦ m | n ↔ (∃ n0. m * n0 = n) subst: [n, m] → [n3, m] flags: rewrite, current

Additional information

Used terms: n3, m