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Proof step 41 from proof divi-same (previous step)

m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, ∃ n0. m * n0 = n3

User applied rule exists right

And obtained the following new goals

Proof step 42:
m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, m * (n1 - n2) = n3

Rule argument

pos: right 3 terms: n1 - n2 abort: F discard: T computed: F

Additional information

Used terms: n1 - n2