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Proof step 42 from proof divi-same (previous step)

m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, m * (n1 - n2) = n3

User applied rule insert elim lemma

And obtained the following new goals

Proof step 43:
m * n2 + n3 = m * n1 ⊦ n2 ≤ n1, n3 + n0 = 0, n3 = 0, m * (n1 - n2) = n3
Proof step 45:
n1 = n4 + n2 ∧ n2 ≤ n1, m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, m * n4 = n3

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n1, n2, n] flags:

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n1, n2, n