| n1 = n4 + n2 ∧ n2 ≤ n1, m * n2 + n3 = m * n1 ⊦ n3 + n0 = 0, n3 = 0, m * n4 = n3 |
m * n2 + n3 = m * (n4 + n2) ⊦ n3 + n0 = 0, n3 = 0, m * n4 = n3
Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lep: ⊦ m ≤ m + n; from specification nat