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Proof step 46 from proof divi-same (previous step)

m * n2 + n3 = m * (n4 + n2) ⊦ n3 + n0 = 0, n3 = 0, m * n4 = n3

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 47:
⊦ m0 * (m + n) = m0 * m + m0 * n

Rule argument

spec: nat-mult inst: name: dist seq: ⊦ m0 * (m + n) = m0 * m + m0 * n subst: [n, m, m0] → [n2, n4, m] flags: rewrite

Additional information

Used simplifier rules: eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: n2, n4, m