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Proof step 11 from proof divi-sub (previous step)

m * n = n1 + n0 ⊦ (∃ n0. m * n0 = n1) ↔ (∃ n1. m * n1 = n0)

User applied rule case distinction

And obtained the following new goals

Proof step 12:
∃ n0. m * n0 = n1, m * n = n1 + n0 ⊦ ∃ n1. m * n1 = n0
Proof step 21:
∃ n1. m * n1 = n0, m * n = n1 + n0 ⊦ ∃ n0. m * n0 = n1

Rule argument

pos: right 1

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