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Proof step 9 from proof divi-sub (previous step)

m * n = n1 + n0 ⊦ (∃ n0. m * n0 = n1) ↔ m | n0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ m | n ↔ (∃ n0. m * n0 = n)
Proof step 11:
m * n = n1 + n0 ⊦ (∃ n0. m * n0 = n1) ↔ (∃ n1. m * n1 = n0)

Rule argument

spec: nat-prime inst: name: Divides seq: ⊦ m | n ↔ (∃ n0. m * n0 = n) subst: [n, m] → [n0, m] flags: rewrite, current

Additional information

Used terms: n0, m