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Proof step 23 from proof gcd-a (previous step)

⊦ gcd(n0, gcd(m, n)) | gcd(m, gcd(n, n0)), gcd(n0, gcd(m, n)) | gcd(n, n0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 24:
⊦ gcd(m, n) = gcd(n, m)
Proof step 25:
⊦ gcd(n0, gcd(m, n)) | gcd(m, gcd(n0, n)), gcd(n0, gcd(m, n)) | gcd(n0, n)

Rule argument

spec: nat-prime inst: name: gcd-c seq: ⊦ gcd(m, n) = gcd(n, m) subst: [n, m] → [n0, n] flags: rewrite, current

Additional information

Used terms: n0, n