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Proof step 25 from proof gcd-a (previous step)

⊦ gcd(n0, gcd(m, n)) | gcd(m, gcd(n0, n)), gcd(n0, gcd(m, n)) | gcd(n0, n)

User applied rule insert lemma

And obtained the following new goals

Proof step 26:
⊦ gcd(m, gcd(n, n0)) | gcd(m, n)
Proof step 27:
gcd(n0, gcd(n, m)) | gcd(n0, n) ⊦ gcd(n0, gcd(m, n)) | gcd(m, gcd(n0, n)), gcd(n0, gcd(m, n)) | gcd(n0, n)

Rule argument

spec: nat-prime inst: name: gcd-div-02 seq: ⊦ gcd(m, gcd(n, n0)) | gcd(m, n) subst: [m, n, n0] → [n0, n, m] flags: current, []

Additional information

Used terms: n0, n, m