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Proof step 5 from proof gcd-conq-one (previous step)

∃ m0. (m * m0) % n = 1, gcd(m, n) = 1 ⊦ n = 1, n = 0, ∃ m0. n | dist(m * m0, 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information