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Theorem gcd-conq-one
gcd(m, n) = 1 ⊦ ∃ m0. n | dist(m * m0, 1)
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 8
Proof steps: 12
Used lemmas:
dist-snd-01
,
Divides
,
gcd-mod-one-01
,
divi-one-01
,
gcd-one
,
dist-eq
,
divi-zero-01
,
gcd-a
,
gcd-zero-02
,
Used spec theorems:
Used simplifier rules:
nat-mult
/
one-01
nat-basic1
/
one-02
nat-div
/
div-elim
nat-basic1
/
one
nat
/
lels-01
nat-basic1
/
one-01
nat-basic2
/
z-01
nat-mult
/
zero-01
nat-mult
/
zero-06
nat-mult
/
mult-a
nat-mult
/
mult-c
nat
/
not-zero
nat-basic2
/
eq-01
nat-basic2
/
a
nat-basic2
/
c
nat
/
elim-pred-c