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Proof step 4 from proof gcd-div-one (previous step)

∃ m0, n0. gcd(m, n) = dist(m * m0, n * n0), gcd(m, n) = 1, m | n * n0 ⊦ m | n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information