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Theorem gcd-div-one

⊦ gcd(m, n) = 1 ∧ m | n * n0 → m | n0

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: gcd-div-one-01, gcd-div-one-02,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 8
Proof steps: 13
Used lemmas: dist-mult, Divides, gcdex-dist,
Used spec theorems:
- nat-mult/mult-a
- nat-mult/mult-c
Used simplifier rules: