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Theorem gcd-mod-one
gcd(m, n) = 1, 1 < n, m ≠ 0 ⊦ ∃ m0. (m * m0) % n = 1
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
gcd-mod-one-01
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 16
Proof steps: 21
Used lemmas:
gcdex
,
Used spec theorems:
nat-mult
/
modeq
nat-mult
/
dist-sub
nat
/
sub-succ
Used simplifier rules:
nat-basic1
/
lf-02
nat-mult
/
ls-08
nat
/
lels
nat-div
/
div-elim
nat-basic1
/
one
nat-basic1
/
f
nat-mult
/
ls-01
nat-mult
/
le-02
nat
/
lels-01
nat-basic1
/
one-01
nat-mult
/
mult-base
nat-basic2
/
z-01
nat-mult
/
rsucc-02
nat
/
add-01
nat-basic2
/
z
nat-mult
/
eq
nat-basic2
/
c
nat-basic2
/
a
nat-mult
/
mult-c
nat-mult
/
mult-a
nat-div
/
mod-one-01
nat-div
/
mod-mult