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Proof step 2 from proof pred-02 (previous step)

n ≤ m ⊦ m - 1 - (n - 1) = m - n, n = 0, m = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1
Proof step 4:
m = m0 + 1, n ≤ m ⊦ m0 - (n - 1) = m - n, n = 0, m = 0

Rule argument

spec: nat inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [m, m0] flags: rewrite, current

Additional information

Used terms: m, m0