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Proof step 4 from proof pred-02 (previous step)

m = m0 + 1, n ≤ m ⊦ m0 - (n - 1) = m - n, n = 0, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n ≤ m0 + 1 ⊦ m0 - (n - 1) = m0 + 1 - n, n = 0

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%oz: ⊦ m + 1 ≠ 0; from specification nat-basic2