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Proof step 12 from proof ordered-postfix (previous step)

ordered≤(a0 ' + y), x ⊒ a ' + a0 ' + y, ∀ x0. x0 ⊒ a0 ' + y → ordered≤(x0) ⊦ a0 < a, ordered≤(x)

User applied rule constructor cut

And obtained the following new goals

Proof step 13:
x = a1 + x1, ordered≤(a0 ' + y), x ⊒ a ' + a0 ' + y, ∀ x0. x0 ⊒ a0 ' + y → ordered≤(x0) ⊦ a0 < a, ordered≤(x)

Rule argument

var: x

Additional information

Used simplifier rules: le-e: ⊦ ordered≤([]);%list freely generated by [], +;;%postfix-empty: ⊦ [] ⊒ x; from specification list-last