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Proof step 13 from proof ordered-postfix (previous step)

x = a1 + x1, ordered≤(a0 ' + y), x ⊒ a ' + a0 ' + y, ∀ x0. x0 ⊒ a0 ' + y → ordered≤(x0) ⊦ a0 < a, ordered≤(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
ordered≤(a0 ' + y), a1 ' + x1 ⊒ a ' + a0 ' + y, ∀ x0. x0 ⊒ a0 ' + y → ordered≤(x0) ⊦ a0 < a, ordered≤(a1 ' + x1)

Rule argument

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list