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Theorem ordered-shorter-sublist

⊦ ordered≤(sublist(m0, n1 + 1, x)) ∧ n2 < n1 ∧ n1 + m0 < # x → (¬ ordered≤(sublist(m0, n2 + 1, x)) ↔ false)

Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 3
Proof steps: 5
Used lemmas: ordered-prefix,
Used spec theorems:
- list-del/sublist-prefix
Used simplifier rules: