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Proof step 28 from proof k-reachable-def (previous step)

r ∈ H, reachable-n(H, n, r, r0) ⊦ r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

User applied rule cut formula

And obtained the following new goals

Proof step 29:
n = 0, r ∈ H, reachable-n(H, n, r, r0) ⊦ r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0
Proof step 31:
r ∈ H, reachable-n(H, n, r, r0) ⊦ n = 0, r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

Rule argument

fma: n = 0

Additional information

Used formulas: n = 0