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Proof step 29 from proof k-reachable-def (previous step)

n = 0, r ∈ H, reachable-n(H, n, r, r0) ⊦ r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
r0 ∈ H ⊦ r0 = null, ∃ x. path(r0 ' + x, H) ∧ (r0 ' + x).last = r0

Rule argument

Additional information

Used simplifier rules: reachable-n-base: ⊦ reachable-n(H, 0, r, r0) ↔ r = r0;