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Proof step 49 from proof rem-stays-reachable-aux (previous step)

H[(r ' + x).last].nxt ≠ (r ' + x).last ∧ r = H[(r ' + x).last].nxt ∨ (∃ x0. path(r ' + x0 + H[(r ' + x).last].nxt ', H) ∧ (r ' + x).last ≠ r ∧ ¬ (r ' + x).last ∈ x0) ∨ (∃ x0. path(H[(r ' + x).last].nxt ' + x0 + H[(r ' + x).last].nxt ', H) ∧ ¬ (r ' + x).last ∈ x0), ce.nxt = H[H[(r ' + x).last].nxt].nxt, path(r ' + x, H), H[(r ' + x).last].nxt ∈ H, (r ' + x).last ∈ H ⊦ reachable(r, H[(r ' + x).last].nxt, H[(r ' + x).last, ce]), H[(r ' + x).last].nxt = ce.nxt, H[(r ' + x).last].nxt = null, r ∈ x, dups(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 50:
ce.nxt = H[H[(r ' + x).last].nxt].nxt, path(r ' + x, H), H[(r ' + x).last].nxt ∈ H, (r ' + x).last ∈ H, H[(r ' + x).last].nxt ≠ (r ' + x).last ∧ r = H[(r ' + x).last].nxt ∨ path(r ' + x0 + H[(r ' + x).last].nxt ', H) ∧ (r ' + x).last ≠ r ∧ ¬ (r ' + x).last ∈ x0 ∨ path(H[(r ' + x).last].nxt ' + x1 + H[(r ' + x).last].nxt ', H) ∧ ¬ (r ' + x).last ∈ x1 ⊦ H[(r ' + x).last].nxt = ce.nxt, H[(r ' + x).last].nxt = null, reachable(r, H[(r ' + x).last].nxt, H[(r ' + x).last, ce]), r ∈ x, dups(x)

Proof step 49 from proof rem-stays-reachable-aux (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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