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Proof step 45 from proof rem-stays-reachable-aux1 (previous step)

x1 + r ' = (x0 + H[r].nxt ') + r1 ' + x, path(H[H[r].nxt].nxt ' + x1 + r ', H), path(H[H[r].nxt].nxt ' + x0 + H[r].nxt ', H), H[r].nxt ∈ H, r ∈ H ⊦ r = H[H[r].nxt].nxt, H[r].nxt = null, H[r].nxt = H[H[r].nxt].nxt, r ∈ x0, H[H[r].nxt].nxt ∈ x1, r ∈ x1, dups(x1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 46:
x1 + r ' = (x0 + H[r].nxt ') + r1 ' + x, r ∈ H, H[r].nxt ∈ H, path(H[H[r].nxt].nxt ' + x0 + H[r].nxt ', H), path(H[H[r].nxt].nxt ' + x1 + r ', H), r = H[r].nxt ∨ r = r1 ∨ r ∈ x ⊦ H[r].nxt = H[H[r].nxt].nxt, H[r].nxt = null, r = H[H[r].nxt].nxt, dups(x1), r ∈ x1, H[H[r].nxt].nxt ∈ x1, r ∈ x0

Rule argument

Additional information

Used simplifier rules: in-rec: ⊦ r ∈ r0 ' + x0 ↔ ¬ ¬(r = r0 ∨ r ∈ x0); from specification list[reflist]%in-append: ⊦ r ∈ x0 + x1 ↔ ¬ ¬(r ∈ x0 ∨ r ∈ x1); from specification list[reflist]%a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist]%in-15: ⊦ x0 + r ' = x1 → r ∈ x1; (forward) from specification list[reflist]