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Proof step 46 from proof rem-stays-reachable-aux1 (previous step)

x1 + r ' = (x0 + H[r].nxt ') + r1 ' + x, r ∈ H, H[r].nxt ∈ H, path(H[H[r].nxt].nxt ' + x0 + H[r].nxt ', H), path(H[H[r].nxt].nxt ' + x1 + r ', H), r = H[r].nxt ∨ r = r1 ∨ r ∈ x ⊦ H[r].nxt = H[H[r].nxt].nxt, H[r].nxt = null, r = H[H[r].nxt].nxt, dups(x1), r ∈ x1, H[H[r].nxt].nxt ∈ x1, r ∈ x0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 47:
x0 ≠ [] ⊦ x1 + r ' = x0 ↔ x1 = x0.butlast ∧ r = x0.last
Proof step 48:
(x0 + H[r].nxt ') + r1 ' + x ≠ [], x1 = ((x0 + H[r].nxt ') + r1 ' + x).butlast ∧ r = ((x0 + H[r].nxt ') + r1 ' + x).last, r ∈ H, H[r].nxt ∈ H, path(H[H[r].nxt].nxt ' + x0 + H[r].nxt ', H), path(H[H[r].nxt].nxt ' + x1 + r ', H), r = H[r].nxt ∨ r = r1 ∨ r ∈ x ⊦ H[r].nxt = H[H[r].nxt].nxt, H[r].nxt = null, r = H[H[r].nxt].nxt, dups(x1), r ∈ x1, H[H[r].nxt].nxt ∈ x1, r ∈ x0

Rule argument

spec: list-last inst: reflist name: splitlasteq seq: x0 ≠ [] ⊦ x1 + r ' = x0 ↔ x1 = x0.butlast ∧ r = x0.last subst: [x0, r, x1] → [(x0 + H[r].nxt ') + r1 ' + x, r, x1] flags: rewrite

Additional information

Used simplifier rules: app-02-ant: ⊦ ¬ x0 + x1 ≠ [] ↔ x0 = [] ∧ x1 = []; from specification list[reflist]%e-01: ⊦ r ' + x0 ≠ []; from specification list[reflist]%a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist] Used terms: (x0 + H[r].nxt ') + r1 ' + x, r, x1