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Proof step 2 from proof rtc+-unfold (previous step)

p+(a, b) ⊦ ∃ c. p(a, c) ∧ p*(c, b)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ p+(a, b) ↔ (∃ n. n ≠ 0 ∧ rtc(n, a, b))
Proof step 4:
∃ n. n ≠ 0 ∧ rtc(n, a, b) ⊦ ∃ c. p(a, c) ∧ p*(c, b)

Rule argument

spec: inst: name: rtc+ seq: ⊦ p+(a, b) ↔ (∃ n. n ≠ 0 ∧ rtc(n, a, b)) subst: [b, a] → [b, a] flags: rewrite, current

Additional information

Used terms: b, a