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Proof step 4 from proof rtc+-unfold (previous step)

∃ n. n ≠ 0 ∧ rtc(n, a, b) ⊦ ∃ c. p(a, c) ∧ p*(c, b)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
rtc(n, a, b) ⊦ n = 0, ∃ c. p(a, c) ∧ p*(c, b)

Rule argument

Additional information