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Proof step 5 from proof rtc+-unfold (previous step)

rtc(n, a, b) ⊦ n = 0, ∃ c. p(a, c) ∧ p*(c, b)

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
n = n0 +1, rtc(n, a, b) ⊦ n = 0, ∃ c. p(a, c) ∧ p*(c, b)

Rule argument

var: n

Additional information

Used simplifier rules: nat freely generated by 0, +1;;