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Proof step 1 from proof del-addeq-02 (conclusion)

⊦ a ∈ s → (s -- a) ++ a = s

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: delete-insert: ⊦ (s -- a) ++ a = s ++ a;%eq: ⊦ a ∈ s → s ++ a = s; from specification set-basic