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Theorem base for Specification set-union

This is a listing of all goals defined over the current specification. Axioms are yellow, proof obligations purple and theorems green. Click on individual names to get more information on the proof.

Name: Sequent: Type:
⊦ a ∈ s1 ∪ s2 ↔ a ∈ s1 ∨ a ∈ s2 An Axiom
⊦ a ∈ s1 ∩ s2 ↔ a ∈ s1 ∧ a ∈ s2 An Axiom
⊦ a ∈ s1 \ s2 ↔ a ∈ s1 ∧ ¬ a ∈ s2 An Axiom
⊦ a ∈ s -- b ↔ a ≠ b ∧ a ∈ s An Axiom
⊦ {a} = ∅ ++ a An Axiom
⊦ ((s0 ++ a) ∩ s1) -- a = (s0 ∩ s1) -- a A User Theorem
⊦ a ≠ b ∧ ¬ a ∈ s ∧ ¬ a ∈ s0 → ((s ++ a) -- b = s0 ++ a ↔ s -- b = s0) A User Theorem
⊦ (s ++ a) -- b -- a = s -- b -- a A User Theorem
⊦ a ∈ s → (s -- a) ++ a = s A User Theorem
⊦ a ∈ s ∧ a ≠ b → (s -- b) ++ a = s -- b A User Theorem
⊦ ¬ a ∈ s → (s ++ a) -- a = s A User Theorem
⊦ (s ++ a) -- a = s -- a A User Theorem
⊦ (s ++ a ++ b) -- a = (s ++ b) -- a A User Theorem
⊦ ¬ a ∈ s → (a ∈ (s -- a0) ++ b ++ c ↔ a = b ∨ a = c) A User Theorem
⊦ ¬ a ∈ s → (a ∈ (s -- b) ++ c ↔ a = c) A User Theorem
⊦ s -- a -- a = s -- a A User Theorem
⊦ s -- a -- b -- a = s -- b -- a A User Theorem
⊦ a ≠ b → (∅ ++ a) -- b = ∅ ++ a A User Theorem
⊦ ¬ a ∈ s → ((s ++ a) -- b = ∅ ↔ s = ∅ ∧ a = b) A User Theorem
⊦ ∅ -- a = ∅ A User Theorem
⊦ s -- a = ∅ ↔ s = ∅ ∨ s = ∅ ++ a A User Theorem
⊦ a ∈ s ∧ a ∈ s0 → (s -- a = s0 -- a ↔ s = s0) A User Theorem
⊦ s -- a = s0 ++ b → a ≠ b ∧ b ∈ s ∧ ¬ a ∈ s0 A User Theorem
⊦ (s ++ a) -- b = s0 ++ c ∧ ¬ c ∈ s → a = c ∧ b ≠ c A User Theorem
⊦ (s ++ a) -- b = s0 ++ c ∧ a ≠ b ∧ ¬ a ∈ s0 → a = c A User Theorem
⊦ ¬ a ∈ s → s -- a = s A User Theorem
⊦ a ≠ b → (¬ a ∈ s -- b ↔ ¬ a ∈ s) A User Theorem
⊦ ¬ a ∈ s -- a A User Theorem
⊦ s -- a = s ↔ ¬ a ∈ s A User Theorem
⊦ 1 < # s → s -- a ≠ ∅ A User Theorem
⊦ s -- a ≠ s0 -- a → s ≠ s0 A User Theorem
⊦ a ≠ b → (s ++ a) -- b ≠ ∅ A User Theorem
⊦ s -- a ≠ s0 ++ a A User Theorem
⊦ s0 = s -- a → ¬ a ∈ s0 A User Theorem
⊦ a ∈ s -- b ↔ ¬ ¬(a ≠ b ∧ a ∈ s) A User Theorem
⊦ a ∈ s → #(s -- a) = # s - 1 A User Theorem
⊦ a ∈ s → (# s = n + 1 ↔ #(s -- a) = n) A User Theorem
⊦ a ∈ s ∧ a ≠ b → #(s -- b -- a) = #(s -- b) - 1 A User Theorem
⊦ 2 < # s → #(s -- a -- b) ≠ 0 A User Theorem
⊦ 2 < # s ∧ b ∈ s ∧ a ≠ b → #(s -- a -- b) = #(s -- a) - 1 A User Theorem
s -- a -- b = ∅ ⊦ s = ∅ ∨ s = ∅ ++ a ∨ s = ∅ ++ b ∨ s = ∅ ++ a ++ b A User Theorem
⊦ (s -- a) ++ a = s ++ a A User Theorem
⊦ a ∈ s → (s -- a = s0 ↔ s = s0 ++ a ∧ ¬ a ∈ s0) A User Theorem
⊦ (s -- a) ++ b ⊆ s ++ b A User Theorem
⊦ a ≠ b → (s ++ b) -- a = (s -- a) ++ b A User Theorem
⊦ s -- b -- a = s -- a -- b A User Theorem
⊦ s -- b -- a = s -- a -- b ↔ true A User Theorem
⊦ s1 \ (s2 ++ a) = (s1 \ s2) -- a A User Theorem
⊦ ¬ a ∈ s1 → s1 \ (s2 ++ a) = s1 \ s2 A User Theorem
⊦ s = s1 \ s2 ∧ ¬ a ∈ s → (s = (s1 -- a) \ (s2 -- a) ↔ true) A User Theorem
⊦ ¬ a ∈ s → s \ s0 ⊆ (s \ s0) -- a A User Theorem
⊦ ¬ a ∈ s → s \ s0 ⊆ ((s \ s0) -- a) ++ b A User Theorem
⊦ (s -- a) \ (s1 -- a) = (s -- a) \ s1 A User Theorem
⊦ ¬ a ∈ s1 → (s -- a) \ s1 = (s \ s1) -- a A User Theorem
⊦ a ∈ s1 → (s -- a) \ s1 = s \ s1 A User Theorem
⊦ a ∈ s1 → (s ++ a) \ s1 = s \ s1 A User Theorem
⊦ ¬ a ∈ s1 → (s ++ a) \ s1 = (s \ s1) ++ a A User Theorem
⊦ a ∈ s2 → (a ∈ s0 \ s1 \ s2 ↔ a ∈ s0) A User Theorem
⊦ s \ ∅ = s A User Theorem
⊦ ∅ \ s = ∅ A User Theorem
⊦ s1 \ s2 = ∅ ∧ a ∈ s1 → a ∈ s2 A User Theorem
⊦ s \ s = ∅ A User Theorem
⊦ (s \ s0) ∩ s0 = ∅ A User Theorem
⊦ (s \ (s0 ∪ s1)) ∩ s0 = ∅ A User Theorem
⊦ s = s1 \ s2 ∧ a ∈ s2 → ¬ a ∈ s A User Theorem
⊦ (∅ ++ a) \ s ⊆ s0 ++ a A User Theorem
⊦ (s \ s1) \ s2 = (s \ s2) \ s1 A User Theorem
⊦ s \ s0 ⊆ s A User Theorem
s = s0 \ s1, s1 ⊆ s0 ⊦ # s = # s0 - # s1 A User Theorem
⊦ s \ (s0 ∪ s1) ⊆ s \ s1 A User Theorem
⊦ ((s -- a) ++ b) \ s0 ⊆ ((s \ s0) -- a) ++ b A User Theorem
⊦ s \ (s ∪ s0) = ∅ A User Theorem
⊦ a ∈ s0 → (a ∈ (s \ s0) ∪ s1 ↔ a ∈ s1) A User Theorem
⊦ ¬ a ∈ s → (a ∈ (s \ s0) ∪ s1 ↔ a ∈ s1) A User Theorem
⊦ ¬ a ∈ s → (a ∈ ((s ∪ s2) \ s0) ∪ s1 ↔ a ∈ (s2 \ s0) ∪ s1) A User Theorem
⊦ (s ∪ s0) \ s1 = (s \ s1) ∪ (s0 \ s1) A User Theorem
⊦ s ∩ s0 = ∅ → s \ s0 = s A User Theorem
⊦ s ++ a = s0 ++ b ∧ s0 ++ b = (s1 -- c) ++ a0 ∧ b ≠ a0 → b ∈ s1 -- c A User Theorem
⊦ ¬ s -- a ⊆ s0 ∧ a ∈ s → ¬ s ⊆ s0 ++ a A User Theorem
⊦ (s ∩ s0) ∩ s1 = s ∩ s0 ∩ s1 A User Theorem
⊦ s ∩ s0 = s0 ∩ s A User Theorem
⊦ s ∩ (s0 -- a) = (s ∩ s0) -- a A User Theorem
⊦ s ∩ ∅ = ∅ A User Theorem
⊦ s ∩ s0 = ∅ ∧ ¬ a ∈ s → s ∩ (s0 ++ a) = ∅ A User Theorem
⊦ s ∩ s0 = ∅ ↔ (∀ a. ¬ a ∈ s ∨ ¬ a ∈ s0) A User Theorem
⊦ s ∩ s0 = ∅ ∧ a ∈ s → (¬ ¬ a ∈ s0 ↔ false) A User Theorem
⊦ (∅ ++ a) ∩ s = ∅ ↔ ¬ a ∈ s A User Theorem
⊦ s = s ∩ s0 ↔ s ⊆ s0 A User Theorem
⊦ s ∩ s = s A User Theorem
⊦ s ∩ (s0 ++ a) = ∅ ↔ s ∩ s0 = ∅ ∧ ¬ a ∈ s A User Theorem
⊦ s ∩ (s0 ++ a) = ∅ → s ∩ s0 = ∅ ∧ ¬ a ∈ s A User Theorem
⊦ a ∈ s → s ∩ (s0 ++ a) ≠ ∅ A User Theorem
⊦ s ∩ s0 = ∅ → (s ∩ (s0 ++ b) ≠ ∅ ↔ b ∈ s) A User Theorem
⊦ s ∩ s0 = ∅ → (s ∩ ((s0 -- a) ++ b) ≠ ∅ ↔ b ∈ s) A User Theorem
⊦ a ∈ s1 ∩ s2 ↔ ¬ ¬(a ∈ s1 ∧ a ∈ s2) A User Theorem
⊦ s ∩ s0 ⊆ s A User Theorem
⊦ (s -- a) ∩ s0 ≠ ∅ → s ∩ s0 ≠ ∅ A User Theorem
⊦ (s0 ++ a) ∩ (s1 -- a) = (s0 ∩ s1) -- a A User Theorem
⊦ s0 ∩ s1 = ∅ → (s0 -- a) ∩ s1 = ∅ A User Theorem
⊦ ¬ a ∈ s → s ∩ (s0 ++ a) = s ∩ s0 A User Theorem
⊦ a ∈ s → s ∩ (s0 ++ a) = (s ∩ s0) ++ a A User Theorem
⊦ ¬ # s0 + # s < #(s0 ∩ s) A User Theorem
s ∩ s0 ≠ ∅ ⊦ ∃ a. a ∈ s ∧ a ∈ s0 A User Theorem
⊦ s ∩ (s0 ∪ s1) = ∅ ↔ s ∩ s0 = ∅ ∧ s ∩ s1 = ∅ A User Theorem
⊦ ¬ b ∈ s ∧ a ≠ b → (s ++ b) -- a = (s -- a) ++ b A User Theorem
⊦ ¬ a ∈ s ∧ a ∈ s0 → s \ s0 = s \ (s0 -- a) A User Theorem
⊦ a ∈ s ∧ a ∈ s0 → s \ s0 = (s -- a) \ (s0 -- a) A User Theorem
⊦ ∅ ∩ s = ∅ A User Theorem
⊦ a ∈ s ∧ a ∈ s0 → s ∩ s0 = ((s -- a) ∩ (s0 -- a)) ++ a A User Theorem
⊦ ¬ a ∈ s ∨ ¬ a ∈ s0 → s ∩ s0 = (s -- a) ∩ (s0 -- a) A User Theorem
⊦ ∅ ∪ s = s A User Theorem
⊦ ¬ a ∈ s ∧ a ∈ s0 → (s ++ a) ∪ s0 = s ∪ s0 A User Theorem
⊦ ¬ a ∈ s ∧ ¬ a ∈ s0 → (s ++ a) ∪ s0 = (s ∪ s0) ++ a A User Theorem
⊦ a ∈ {b} ↔ a = b A User Theorem
⊦ s = ∅ ++ a → s -- a = ∅ A User Theorem
⊦ (s0 \ s1) ∩ s = ∅ ∧ (s2 \ s0) ∩ s = ∅ → (s2 \ s1) ∩ s = ∅ A User Theorem
⊦ (s0 ∪ (s1 -- a)) ++ a = (s0 ∪ s1) ++ a A User Theorem
s1 ⊆ s2 ⊦ s1 = s2, ∃ s. s ⊆ s2 ∧ s1 = s2 \ s A User Theorem
⊦ # s ≤ #(s -- a) ↔ ¬ a ∈ s A User Theorem
⊦ s0 = s1 → (# s0 ≠ # s1 ↔ false) A User Theorem
∀ a. a ∈ s0 ↔ a ∈ s1 ⊦ # s0 ≠ # s1 ↔ false A User Theorem
⊦ s ∩ s0 = ∅ → #(s ∪ s0) = # s + # s0 A User Theorem
⊦ s ⊆ s0 → (s -- a) ++ b ⊆ (s0 -- a) ++ b A User Theorem
⊦ s ⊆ s0 → (s -- a) ++ b ++ c ⊆ (s0 -- a) ++ b ++ c A User Theorem
⊦ s ⊆ s0 ∧ ¬ a ∈ s → s ⊆ (s0 -- a) ++ b A User Theorem
⊦ s ⊆ s0 ∧ ¬ a ∈ s → s ⊆ (s0 -- a) ++ b ++ c A User Theorem
⊦ s ⊆ s0 → s -- a ⊆ s0 -- a A User Theorem
⊦ s ⊆ s0 ∧ ¬ a ∈ s → s ⊆ s0 -- a A User Theorem
⊦ s -- a ⊆ s A User Theorem
⊦ s ⊆ s0 → s -- a ⊆ s0 A User Theorem
⊦ s ⊆ s0 -- a ↔ s ⊆ s0 ∧ ¬ a ∈ s A User Theorem
⊦ a ≠ b ∧ ¬ a ∈ s → s -- b ⊆ s -- b -- a A User Theorem
⊦ s ⊆ s0 → s ⊆ s0 ∪ s1 A User Theorem
⊦ s ⊆ s0 → s ⊆ (s0 ∪ s1) ++ a A User Theorem
⊦ s ⊆ (s ∪ s0) ++ a ++ b A User Theorem
⊦ s ++ a ⊆ (s ∪ s0) ++ a A User Theorem
⊦ s ++ a ⊆ (s ∪ s0) ++ b ++ a A User Theorem
⊦ s ⊆ (s ∪ s0) ++ a ++ b ++ c A User Theorem
⊦ s1 ⊆ s2 ↔ (∀ a. a ∈ s1 → a ∈ s2) A User Theorem
⊦ s ⊆ s -- a ↔ ¬ a ∈ s A User Theorem
⊦ s ⊆ s0 ↔ (∃ s1. s ∪ s1 = s0 ∧ s ∩ s1 = ∅) A User Theorem
⊦ s0 ⊆ s1 ∧ s1 ∩ s2 = ∅ → s0 ∩ s2 = ∅ A User Theorem
⊦ a ∈ s0 ∧ s0 ⊆ s1 → s1 \ (s0 -- a) = (s1 \ s0) ++ a A User Theorem
⊦ s -- a ⊆ s0 ∧ ¬ s ⊆ s0 ∧ a ∈ s → ¬ a ∈ s0 A User Theorem
⊦ (s ∪ s0) ∪ s1 = s ∪ s0 ∪ s1 A User Theorem
⊦ (s ++ a) ∪ s0 = (s ∪ s0) ++ a A User Theorem
⊦ s ∪ (s0 ++ a) = (s ∪ s0) ++ a A User Theorem
⊦ s = s0 ∪ s ↔ (∀ a. a ∈ s0 → a ∈ s) A User Theorem
⊦ s ∪ s0 = s0 ∪ s A User Theorem
⊦ a ∈ s → s ∪ (s0 -- a) = s ∪ s0 A User Theorem
⊦ (s ∪ s0) -- a = s ∪ (s0 -- a) ↔ ¬ a ∈ s A User Theorem
⊦ (s ∪ s0) -- a = (s -- a) ∪ (s0 -- a) A User Theorem
⊦ ¬ a ∈ s → s ∪ (s0 -- a) = (s ∪ s0) -- a A User Theorem
⊦ (s -- a) ∪ (s0 -- a) = (s ∪ s0) -- a A User Theorem
⊦ ¬ a ∈ s ∧ ¬ a ∈ s0 → (s -- a) ∪ (s0 -- a) = s ∪ s0 A User Theorem
⊦ (s -- a -- b) ∪ s0 ≠ (s -- b -- a) ∪ s0 ↔ false A User Theorem
⊦ s ∪ ∅ = s A User Theorem
⊦ s1 ∪ s2 = ∅ ↔ s1 = ∅ ∧ s2 = ∅ A User Theorem
⊦ s ∪ s0 = s0 ↔ s ⊆ s0 A User Theorem
⊦ s ∪ s = s A User Theorem
⊦ ¬ a ∈ s → (a ∈ s ∪ s0 ↔ a ∈ s0) A User Theorem
⊦ ¬ a ∈ s ∪ s0 ↔ ¬ a ∈ s ∧ ¬ a ∈ s0 A User Theorem
⊦ ¬ a ∈ s ∪ s0 → ¬ a ∈ (s -- b) ∪ s0 A User Theorem
⊦ a ∈ s → (s ∪ s0) ++ a = s ∪ s0 A User Theorem
⊦ ¬ a ∈ s ∪ s0 ∧ s1 ⊆ s → ¬ a ∈ (s1 -- b) ∪ s0 A User Theorem
⊦ a ∈ (s -- a) ∪ s0 ↔ a ∈ s0 A User Theorem
⊦ ¬ a ∈ s0 ∧ ¬ a ∈ s1 → (a ∈ s \ (s0 ∪ s1) ↔ a ∈ s) A User Theorem
⊦ (s0 ∪ s1) \ (s2 ∪ s1) = s0 \ (s2 ∪ s1) A User Theorem
⊦ s ⊆ s0 → s ∪ (s0 \ s) = s0 A User Theorem
⊦ (s0 ∪ s1) ∩ s2 = (s0 ∩ s2) ∪ (s1 ∩ s2) A User Theorem
⊦ a ≠ b → (a ∈ {b} ∪ s ↔ a ∈ s) A User Theorem
⊦ a ∈ s0 → ((s0 -- a) ∪ s1) ++ a = s0 ∪ s1 A User Theorem
⊦ (s0 -- a) ∪ s1 = s0 ∪ s1 ↔ a ∈ s1 ∨ ¬ a ∈ s0 A User Theorem
⊦ s0 ⊆ s2 → s0 \ s1 ⊆ s2 A User Theorem
⊦ s ++ a = s ∪ {a} A User Theorem
⊦ ¬ #(s ∪ s0) < # s A User Theorem
⊦ ¬ a ∈ s → ¬ #((s ∪ s0) ++ a) ≤ # s A User Theorem
⊦ ¬ a ∈ s ∧ a ∈ s0 → #(s ∪ s0) = #(s ∪ (s0 -- a)) + 1 A User Theorem
⊦ #(s0 ∪ s1) = # s0 + # s1 - #(s0 ∩ s1) A User Theorem
⊦ ¬ a ∈ s ∧ ¬ a ∈ s0 → #((s ∪ s0) ++ a) = #(s ∪ s0) + 1 A User Theorem
⊦ #(s0 ∪ s1) ≤ # s0 + # s1 A User Theorem
⊦ a ∈ s0 ∧ a ∈ s1 → #(s0 ∪ s1) < # s0 + # s1 A User Theorem
⊦ ¬ # s0 + # s1 < #(s0 ∪ s1) A User Theorem
⊦ # s0 ≤ m ∧ # s1 ≤ n → ¬ m + n < #(s0 ∪ s1) A User Theorem
⊦ # s0 ≤ m ∧ # s1 ≤ n → ¬ m + n + 1 < #(s0 ∪ s1) A User Theorem
⊦ #(s ∪ s0) = # s ↔ s0 ⊆ s A User Theorem
⊦ #(s ∪ s0) ≤ # s ↔ s0 ⊆ s A User Theorem
⊦ #((s ∪ s0) ++ a) ≤ # s ↔ s0 ⊆ s ∧ a ∈ s A User Theorem
⊦ s0 ⊆ s → s ∪ s0 = s A User Theorem
⊦ s0 ⊆ s → s0 ∪ s = s A User Theorem
⊦ s ⊆ s0 → s ∪ s1 ⊆ s0 ∪ s1 A User Theorem
⊦ ¬ s ∪ s1 ⊆ s0 ∪ s1 → ¬ s ⊆ s0 A User Theorem
⊦ s ⊆ s0 ∧ s1 ⊆ s2 → s ∪ s1 ⊆ (s0 ∪ s2) ++ a A User Theorem
⊦ s ⊆ s0 ∧ s1 ⊆ s2 ∧ s3 ⊆ s4 → s ∪ s1 ∪ s3 ⊆ s0 ∪ s2 ∪ s4 A User Theorem
⊦ s ⊆ s0 ∧ s1 ⊆ s2 ∧ s3 ⊆ s4 → s ∪ s1 ∪ s3 ⊆ (s0 ∪ s2 ∪ s4) ++ a A User Theorem
⊦ s ⊆ s0 → s ∪ s1 ⊆ (s0 ∪ s1) ++ a A User Theorem
⊦ s0 ∪ s1 ⊆ s2 ∪ s1 ↔ s0 ⊆ s2 ∪ s1 A User Theorem
⊦ a ∈ s ∪ s0 ↔ ¬ ¬(a ∈ s ∨ a ∈ s0) A User Theorem
⊦ s ⊆ s ∪ s0 A User Theorem
⊦ s1 ∪ s2 ⊆ s ↔ s1 ⊆ s ∧ s2 ⊆ s A User Theorem
⊦ s ⊆ s0 ∧ s1 ⊆ s2 ∧ ¬ a ∈ s ∧ ¬ a ∈ s1 → s ∪ s1 ⊆ (s0 -- a) ∪ (s2 -- a) A User Theorem
⊦ s ⊆ s0 ∧ ¬ a ∈ s → (s0 -- a) ∪ s = s0 -- a A User Theorem
⊦ s ++ a ⊆ s ∪ s0 ↔ a ∈ s ∪ s0 A User Theorem
⊦ s ⊆ (s ∪ s0) ++ a A User Theorem
⊦ s ⊆ s0 ∧ s1 ⊆ s2 → s ∪ s1 ⊆ s0 ∪ s2 A User Theorem