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Proof step 23 from proof del-two (previous step)

a4 ∈ s, a0 ∈ s, a ∈ ∅ ++ a ++ b, ∀ a1. a1 = b ∨ ¬ a1 ∈ s ⊦ a2 ∈ s, a2 ∈ s ↔ a2 = b, a ∈ s

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
a ∈ ∅ ++ a ++ b, a0 ∈ s, a4 ∈ s, ∀ a1. ¬ a1 ∈ s ⊦ a ∈ s, b ∈ s

Rule argument

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