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Proof step 17 from proof intersection-size (previous step)

# s0 + # s1 < #(s0 ∩ s1), a ∈ s1, ∀ s0. # s0 + # s1 < #(s0 ∩ s1) → #(s0 ∩ s1) = 0 ∨ s0 ∩ s1 = ∅ ⊦ s1 = ∅, s0 ∩ s1 = ∅, #(s0 ∩ s1) = 0, # s1 = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: s0

Additional information

Used terms: s0