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Proof step 8 from proof intu-empty (previous step)

a0 ∈ s1, a0 ∈ s, ∀ a. ¬ a ∈ s ∨ ¬ a ∈ s0 ∧ ¬ a ∈ s1 ⊦ s1 = ∅, s = ∅, # s1 = 0, # s = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a0

Additional information

Used terms: a0