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Proof step 1 from proof rem-union-ins (conclusion)

⊦ (s0 ∪ (s1 -- a)) ++ a = (s0 ∪ s1) ++ a

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 2:
a ∈ s1 ⊦ (s0 ∪ (s1 -- a)) ++ a = (s0 ∪ s1) ++ a

Rule argument

fma: a ∈ s1

Additional information

Used simplifier rules: del-in: ⊦ ¬ a ∈ s → s -- a = s; Used formulas: a ∈ s1