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Proof step 10 from proof selsub-diff (previous step)

a1 ∈ s1, a0 ∈ s1, ∀ a. a ∈ s1 → a ∈ s2 ⊦ a ∈ s1 ↔ a ∈ s2, a1 ∈ s2, a1 ∈ s2 \ s1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a1

Additional information

Used terms: a1