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Proof step 7 from proof size-eq-ext (
previous step
)
∀ a. a ∈ s0 ↔ a ∈ s1 ⊦ # s0 = # s1, a ∈ s0 ↔ a ∈ s1
User applied rule all left
And closed the goal!
Rule argument
pos: left 1 terms: a abort: F discard: F computed: T
Additional information
Used terms: a